b^2-10b-96=0

Solution for b^2-10b-96=0 equation:

Simplifying
b2 + -10b + -96 = 0

Reorder the terms:
-96 + -10b + b2 = 0

Solving
-96 + -10b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-6 + -1b)(16 + -1b) = 0

Subproblem 1
Set the factor '(-6 + -1b)' equal to zero and attempt to solve:

Simplifying
-6 + -1b = 0

Solving
-6 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + -1b = 0 + 6

Combine like terms: -6 + 6 = 0
0 + -1b = 0 + 6
-1b = 0 + 6

Combine like terms: 0 + 6 = 6
-1b = 6

Divide each side by '-1'.
b = -6

Simplifying
b = -6
Subproblem 2
Set the factor '(16 + -1b)' equal to zero and attempt to solve:

Simplifying
16 + -1b = 0

Solving
16 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + -1b = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -1b = 0 + -16
-1b = 0 + -16

Combine like terms: 0 + -16 = -16
-1b = -16

Divide each side by '-1'.
b = 16

Simplifying
b = 16
Solution
b = {-6, 16}